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6x^2+12x=18-35x
We move all terms to the left:
6x^2+12x-(18-35x)=0
We add all the numbers together, and all the variables
6x^2+12x-(-35x+18)=0
We get rid of parentheses
6x^2+12x+35x-18=0
We add all the numbers together, and all the variables
6x^2+47x-18=0
a = 6; b = 47; c = -18;
Δ = b2-4ac
Δ = 472-4·6·(-18)
Δ = 2641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{2641}}{2*6}=\frac{-47-\sqrt{2641}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{2641}}{2*6}=\frac{-47+\sqrt{2641}}{12} $
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